Use Super type can change program behavior. It does not check that after changing type another variant of overloaded
method can by called.

Steps to reproduce:
1) have class SubClass extending class SuperClass
2) have a class Test:
public class Test {

    public void method() {
        SubClass sub = new SubClass();
        action(sub);
    }
    
    public void action(SubClass sc) {
        System.out.println("Called on subclass");
        sc.subMethod();
    }
    
    public void action(SuperClass sc) {
        System.out.println("Called on superclass");
        sc.superMethod();
    }
    
    public static void main(String[] args) {
        new Test().method();       
    }
}

3) call Use Supertype on SubClass and select SuperClass as target type
-> the type of 'sub' is changed to SuperType and as result another variant of action method is called