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The sorting of nodes in tree table view is hard-coded. There are just compared display names. This is not sufficient in some cases (see issue #55226). IMHO a similar approach that is used for properties should be implemented. In TreeTableView.SortedNodeTreeModel.getRowComparator() I would expect e.g. a check whether the Node implements Comparable and use that comparable instead of n1.getDisplayName().compareTo(n2.getDisplayName()).
fixed in core-main/rev/de50002894c7